Calendars  Solved Problems
For
complete understanding of concept of Calendars,go through Concept of Calendars
Problems
on Calendars Solved Problem 1
How
many days are there from 3^{rd} February, 2012 to 18^{rd} April
2012 (both inclusive)?
a) 76 days
b)82 days c)85 days
d)92 days e)95 days
Answer
: A
Explanation
:
The number days
from 3^{rd} February, 2012 to 18^{rd} April 2012
( both inclusive)
The
given year is leap year , So February month has 29 days .
From 3rd February to 29^{th} February
=27 days

March = 31 days

From 1^{st} April to 18^{th} April = 18 days

Total number of days = 76 days

Problems
on Calendars Solved Problem 2
How many days are there from 22^{nd}
Jan 2018 to 15^{th} May 2019?
a) 485 days b)394 days c)479 days d)504 days e) None of these
Answer :
Explanation :
From 22^{nd}
January 2018 to 21^{st} January 2019 = 365 days

January 2019
= 10 days

February 2019 = 28 days

March
2019 = 31 days

April 2019 = 30 days

May 2019 = 15 days

Total number of days = 479 days

Problems
on Calendars  Solved Problem 3
Find
the number of odd days in 123 days
a) 0 b)1 c)2 d)4
e) 5
Answer:
D
Explanation:
Odd days =>The number of days more
than complete number of weeks in the given period
123 days = (19 x 7 days ) + 4 => 19
weeks + 4 days
Therefore, the number of odd
days in 123 days is 4.
Problems on Calendars –Solved
Problems 4.
Find the number of odd
days on 200 days.
a)3 b)4 c) 5 d)
6
e) None of these
Answer:B
Explanation :
200 days = (7 days x 28)+ 4
= 28 weeks + 4 days
The number of odd days = 4.
Solved Problems on Calendars Problem 5
How
many odd days are there from 13^{th} May, 2005 to 19^{rd} August
2005 (both inclusive)?
a)
0 b)1
c)2
d)4 e)6
Answer
: B
Explanation
:
The number days from 13^{th} May, 2005 to 18^{rd} August
2005 ( both inclusive)
From 13^{th} May to
to 31st May = 19
days

June
= 30 days

July =
31 days

From 1^{st} August
to 19^{th} August = 19 days

Total number of days = 99 days

The number of odd days =(14 x 7 days )+ 1 =99
So there is 1 odd day in
the given period
Problems on Calendars – Solved
Question 6
Find the number of odd
days in 49 consecutive years
a) 3 b) 4 c) 5 d) 6 e)None of these
Answer : C
Explanation :
49 years = 37
ordinary years + 12 leap years
= (37 x 1 odd days ) + (12 x 2 odd days)
=
61 odd days i.e, 5 odd days
Solved
Questions on Calendars Problem 7
Find
the number of odd days in 126 consecutive years.
a)0 b)1 c)2 d)3 e)4
Answer
: C
Explanation
:
A period of 100
consecutive years has 5 odd days .
In 26 years , 4 years
are leap years and remaining are
ordinary years
125 years = 100 years
+ 26 years
= 100
years + 6 leap years + 20 ordinary years
= 5 odd days + 12 odd days + 20 odd days
=37 odd days = (5 x 7) +2= 2 odd days
Aptitude Questions on Calendars
– Problems 8
Find the number of odd
days in 425 consecutive years.
a)
3 b) 4 c) 5 d) 6 e) None of these
Answer : A
Explanation :
425 years = 400 years + 25 years
A period of 400 years consists of 0 odd
days .
In 25 years,
there are 6 leap years and 19 ordinary years.
Number of odd days = 0 odd days + (6 x 2
odd days ) + ( 19 x 1 odd day )
=
31 odd days i.e, 3 odd days
Aptitude Questions on Calendars Solved Problem 9
Today
is Thursday. What will be the day of the week after 94 days?
a)
Sunday b) Monday
c) Tuesday d)
Saturday e) Wednesday
Answer
: A
Explanation
:
94 days=(13×7 days )+3
= 13 weeks
+ 3 days
=3 odd
days.
The day of the week
on the 94^{th} day will be => (Thursday + 3 days ) i.e., Sunday
Problems on Calendars  Solved Questions 10
Today is Sunday. After
54 days it will be ….
a)
Saturday b) Sunday c)Friday d) Monday e)Tuesday
Answer : C
Explanation :
54 days = (7 x 7 days)
+ 5 days
= 7 complete weeks + 5 extra
days
= 5 odd days
After 54dauys , it will be => 5 days after Sunday. i.e. Friday.
Aptitude questions on Calendars Solved Problem 11
Today
is Thursday. What day of the week it was 30 days before?
a) Monday b)
Tuesday c)
Wednesday d) Friday
e)Saturday
Answer: B
Explanation:
30 days = (4 x 7 )+ 2
= 4 complete
weeks + 2 extra days
= 2 odd days
The day was 2 days before
Thursday i.e Tuesday
Problems
on Calendars Solved Problem 12
It was
Thursday on 12^{th} January 2006. What day of the week it will be
on January 12^{th} 2007?
a)
Tuesday b)
Wednesday c)
Thursday d) Friday
e)Sunday
Answer
: D
Explanation
:
There is exactly 1
year , (365 days) between the two dates .
2006 is an ordinary
year. It has one odd day.
The day of the week
on January 12^{th} 2007 is one day after Thursday=> Friday
Aptitude Questions on Calendarss
– Solved Question 13
January 1st 2004 was Thursday.
What day of the week will it be on January 1st 2005.
a)
Sunday b) Monday c)
Saturday d)Tuesday e)Friday
Answer : C
Explanation :
1994 is an
ordinary year and Jan 1st lies before the month of Feb.
So the whole year has one odd day.
The day is one day after Wednesday. i.e.
Thursday.
Aptitude
Questions on Calendars Solved Problem 14
Today
is 5^{th} August. The day of the week is Wednesday. This is a leap
year. What will be the day of the week on this date after 3 years?
a)
Monday b)
Wednesday c)
Thursday d) Saturday e)Sunday
Answer: D
Explanation:
The present
year is a leap year.
So none of the next 3 years will be a leap year.
Each ordinary year has one odd day, so there will be 3 odd days in next 3
years.
So the day of the
week will be 3 days after Wednesday i.e. it will be Saturday
Aptitude Questions – Calendars
Solved Problem 15
Today is 20th March. The
day of the week is Thursday. This year is a leap year. What will be the day of
the week on this date after 2 years?
a)Sunday b)Saturday c)Friday d)Tuesday e) Monday
Answer: B
Explanation :
This year being a
leap year. None of the next two years will be a leap year.
Number of odd days in two ordinary years is
2.
So the day of the week will be two days after
Thursday i.e., Saturday.
Solved Questions on Calendars –
Solved Problem 16
Today is 5th Feb. The
day of the week is Sunday. Last year was a leap year. The day of the week in
this date before three years was
a)Wednesday b)Thursday c)Tuesday d)Sunday e) Monday
Answer: A
Explanation :
Given that the
last year was leap year.
In last 3 years ,
2 years were ordinary years and one year was a leap year.
∴ The number of odd days in 3 years = 4.
⇒ The day was 4 days before Sunday. i.e.,
Wednesday.
Problems
on Calendars Solved Problem 17.
Given
that 18th April 1603 is a Thursday. What was the day of week on 18^{th} April
2003?
a) Tuesday b)
Wednesday c)
Thursday d)
Sunday e) Monday
Answer : C
Explanation:
After
every 400 years, the same day occurs. (Because a period of 400 years has 0 odd
days)
Given that 18th April
1603 is a Thursday.
After 400 years i.e.,
on 18^{th} April 2003 has to be Thursday.
Aptitude Questions on Calendars Solved Problem 18
1^{st} January
2005 was Sunday . What day of the week was 1^{st} January 2004 ?
a)
Monday b) Tuesday
c) Thursday d) Friday e)
Sunday
Answer: D
Explanation:
Number
of days from 1^{st} January 2004 to 1^{st} January
2005 = 366 days
(2004 is leap year
and February 29^{th} is taken while counting the number of days )
So the number of odd days is 2 odd days.
The day was two days before Sunday, i.e
Friday
Problems
on Calendars Solved Problem 19
It was
Tuesday on 4^{th} January 2013. What day of the week will be on 18^{th} March
2013 ?
a)
Tuesday b)
Wednesday c)
Thursday d )
Friday
e)Saturday
Answer
: D
Explanation: Total number of days from 4^{th} January
2013 to 17^{th} March 2013
= January + February + March
=
27 +
28 + 18
=
73 days
Number of odd days = (10 x 7) + 3 = 3 odd days
The day is 3 days after Tuesday, i.e, Friday.
Aptitude
Questions on Calendars Solved Problem 20
12.
Find the day of the week on 15^{th} August
1947?
a) Monday b)
Tuesday
c) Thursday d)
Friday e) Sunday
Answer : D
Explanation:
15^{th} August
1947 means = 1946 years+7 months + 15 days
=1900 +46 years+7 months+15 days
1600 years have 0 odd days and 300 years have
1 odd day.
Number of odd days 1900 years = 0+1 = 1 odd
days
46 years = 11 leap years + 35 ordinary years
=> (11 x 2)+ (35 x 1) =57 i.e,1 odd day
In the year 1947
=> 31+28+31+30+31+30+31+15
=3+0+3+2+3+2+3+1
=17 i.e, 3 odd days
Total odd days = 1+1+3 =5 odd days
Hence , the given
day is Friday
The
day of the week is counted according to the number of odd days left
Odd days left

Day of the week

0

Sunday

1

Monday

2

Tuesday

3

Wednesday

4

Thursday

5

Friday

6

Saturday

Aptitude Questions on calendars
– Solved Problems 21
What day of the week on
20th September 1972
a)
Tuesday b) Wednesday c)
Thursday d) Friday e)
None of these
Answer : B
Explanation :
20th September 1972 means 1971 years + 8
months + 20 days.
1971 = 1600 years + 300 years + 71 years
1600 years have 0
odd days and 300 years have 1 odd day.
The number of odd days
in 1900 years = 1
In 71 years there
are 17 leap years and 54 ordinary years
= > (17 x 2 ) + (54 x 1)= 88 odd days i.e, 5 odd days
The number of the
days from 1^{st} January 1972 to 20^{th} sept 1972 is
= 31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 +
20
= 26 odd day = 5 odd days
Total number of odd days = 1+5+5 = 11 = 4
odd days
Hence the day on 20^{th} September 1972
was Thursday.
Aptitude Questions on Calendars Solved Problem 22
On what
dates of April 2009 did Thursday fall
a)1,8,15,22,29 b)2,9,16,23,30 c)3,10,17,24 d)4,11,18,25 e)5,12,19,26
Answer : B
Explanation:
We first find , the day of the week on 1^{st} April
2009.
1^{st} April 2009 means, 2008 years 3 months
and 1 day
= 2000 years + 8
years + January + February + March + 1^{st} April
= 0 odd days+2 leap years+ 6 ordinary years + 31 days+28 days+31
days + 1 day
= 0+ 4 odd days + 6 odd days +
3 odd days + 0 odd days +3 odd days + 1 odd day
=17 odd days = 3 odd days
From the date in the above problem, when number of days is 3, the
day of the week becomes Wednesday.
Thus, first Thursday falls on 2^{nd} April.
In
that month, Thursday falls on 2^{nd} , 9^{th} ,16^{th},
23^{rd} and 30^{th}.