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* *__Wipro Placement Papers with answers - Model Questions __

__Wipro Placement Papers with answers - Model Questions__

###
Wipro Placement Questions Models solved –Question
1

###
Today is Monday. After 61 days, it will be

a) Wednesday b) Saturday c) Tuesday d)Thursday

###
Answer : C

### Explanation :

###
The
number of odd days in 61 days = 61/7 = 5 odd days

###
After 61 days . the day of the week
will be = Monday + 5 =Saturday

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**Wipro Placement Papers solved - Model Question 2**
Today is
Wednesday. What will be the day after 94 days ?

a)Monday b)
Tuesday c)
Wednesday d) Saturday

**Answer :
D**
**Explanation:**
94
days = (13 x 7 days)+ 3 days
In a period of 94 days , we
have 13 weeks and 3 days .
So the number of odd days in 94 days
is 3.

Today is Wednesday, the day of the week after 94
days = Wednesday + 3 =Saturday

**Wipro
Placement Papers Solved – Problems on Calendars Model Question 3**
Today is
Thursday. The day after 59 days will be?

a) Sunday b)
Monday c) Tuesday d) Wednesday

**Answer :
A**
**Explanation :**
The number of odd days is the remainder when the given period
of days is divided by 7.
59 days =( 7 days x 8 ) + 3 days

. So the number of odd days is 3.

The day of the week after 59 days will be = Thursday
+ 3 days = Sunday

**Wipro Placement Model Questions – Problems on
Calendars Question 4**
If the day that will dawn 2 days after tomorrow
is Friday, what day of the week dawned two days before yesterday?

a) Wednesday b)
Friday c) Thursday d) Sunday

**Answer :
D**
**Explanation:**
The day that will dawn 2 days
after tomorrow= 3 days after today i.e Friday
So today is Friday – 3 = Tuesday.
Day dawned two days before
yesterday = 3 days before today
The day of the week 3 days before today
is Tuesday – 3 = Saturday

**Wipro Previous
Placement Questions solved – Calendars Model Question 5**
15^{th} August of a year falls on Wednesday, then
what day is the 2nd October in that year?

a) Wednesday b)
Tuesday c) Monday d) Sunday

**Answer :B**
**Explanation:**

Number
of days from 16th august and 2nd October is
August 31 -15
= 16 days
September 30 days
October 2
days
------------
=48 days
The number of odd
days in 48 days= 6 weeks + 6 days = 6 odd days
The day of the week on 2^{nd} October
= Wednesday + 6 = Tuesday

**Wipro Placement Papers solved – Model Question 6**
January 1, 2008 is Tuesday. What
day of the week lies on Jan 1, 2009?

a) Monday b)
Wednesday c) Thursday d) Sunday
**Answer : C**
**Explanation** : The
number of days from January 1, 2008 to January 1^{st} , 2009= 366 days
( Because 2008 is a leap year )
366 days =
52 weeks + 2 days
The number of odd days = 2
So
January 1^{st} ,2009 is 2 days after Tuesday = Tuesday + 2 =Thursday

**Wipro Previous Placement Model Questions
– Problems on Calendars 7**
On
8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?

a)Sunday b)Thursday c)Tuesday d) Friday

**Answer: D**
**Explanation:** The
number of day from 8^{th} December 2007 to 8^{th} December
2006= 365 days = 52 weeks + 1 day.
So the number of
odd days is 1 .
So Dec 8th
2006 is behind one day = Saturday – 1 = Friday

**Wipro
Placement Papers solved –Calendars Model
Question 8**
On 8th Feb, 2005 it was Tuesday. What was the day of the week
on 8th Feb, 2004?

a) Tuesday b)
Monday c) Sunday d) Wednesday

**Answer :
C**

Explanation:
The number days between 2 dates = 366 days (Since
2004 is a leap year and while we are
counting the number of days , February 29th is taken)
Therefore two
days will be preceded from Tuesday
Day
of the week on 8^{th} February = Tuesday -2 = Sunday

**Wipro Placement Questions Solved –Model Question 9**
On 8th march,
2005, Wednesday falls. What day of the
week was it on 8th march, 2004?

a) Monday b)
Tuesday c) Wednesday d) Friday

**Answer :
B**

Explanation **:** The number of days between 2
dates is = 365 days ( 2004 is a leap year , but while counting the number of
days , February 29^{th} is not taken )
The number of odd days =1
Day of the week on 8^{th}
March 2004 is 1 day behind the Wednesday = Wednesday -1 = Tuesday

**Wipro Placement Papers - Problems on Calendars Model
Question 10**
The first
republic day of the India was celebrated on 26th January,1950. It was

a) Monday b)
Wednesday c) Thursday d) Friday

**Answer :C**
**Explanation :** January 1^{st} 1 AD falls on Monday.
Now we have to calculate the
number of days from January 1^{st} , 1 A.D to 26^{th} January , 1950.

1950 January 26^{th} can be written as = 1600 years + 300 years + 49
years + 26

Number of odd days till 1600 years = 0

1600 to 1900 = 300 years = 1 odd day.

49 years contains = 37 ordinary years + 12 leap
years =37 + (12 × 2)
=
61 odd days = 61/7 = 5 odd days

In January , 25 days = 25/7 =4 odd days

Total odd days =0 + 1 + 5 + 4 = 10/7 = 3 odd days

So 26th January,1950 is Monday + 3 = Thursday

**Wipro Placement Papers– Model Problems on
Calendars 11**
Find the day of
the week on 25th December, 1995?

a) Monday b)
Wednesday c) Friday d) Sunday

**Answer :
A**

Explanation :

January 1^{st} 1 AD
falls on Monday.
Now we have to calculate the
number of days from January 1^{st} , 1 A.D to 25^{th}
December , 1995.

1950 January 26^{th} can be written as = 1600 years + 300 years + 94 years
+ and months up to November + 25 days in December

Number of odd days till 1600 years = 0

1600 to 1900 = 300 years = 1 odd day.

94 years contains = 71 ordinary years + 23 leap
years
=71 + 23 × 2 = 117 odd days
= 117/7 = 5 odd days
Odd days , month wise from
January to December
Ã° 3 + 0 + 3 +
2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 25 = 51/7=2
odd days
So total odd days =0 + 1 + 5
+2 = 1 odd days

So 25th December 1995 falls on Monday+1 = Tuesday

**Wipro Latest Placement Questions
– Model Question 12**
Find
the day of the week on 16th July, 1776.
a)
Sunday b) Monday c) Tuesday d) Wednesday

**Answer: c**

Explanation:
January 1^{st} 1 AD
falls on Monday.
Now
we have to calculate the number of days from January 1^{st}, 1 A.D to
16^{th} July, 1776.

1950 January 26^{th} can be written as = 1600 years + 100 years + 75
years + January to June months + July 16
days

Number of odd days till 1600 years = 0

1601 to 1700 = 100 years = 5 odd days

1701 to 1775 = 18 leap years + 57
ordinary years
= (18 x 2 odd days) + 57 = 36 + 57 =93 odd days i.e, 2 odd days

No of odd days
upto 15th July 1776 = 31 + 29 + 31 + 30 + 31 + 30 + 15 = 197 = 1 odd
day.

Total odd days = 5 + 2 + 1 = 8 = 1 odd day.

Hence , 15^{th} July 1776 falls
on => Monday + 1 = Tuesday

**Wipro Placement Papers solved - Model Question 2**

a)Monday b) Tuesday c) Wednesday d) Saturday

**Answer : D**

**Explanation:**

Today is Wednesday, the day of the week after 94 days = Wednesday + 3 =Saturday

**Wipro Placement Papers Solved – Problems on Calendars Model Question 3**

a) Sunday b) Monday c) Tuesday d) Wednesday

**Answer : A**

**Explanation :**

. So the number of odd days is 3.

The day of the week after 59 days will be = Thursday + 3 days = Sunday

**Wipro Placement Model Questions – Problems on Calendars Question 4**

a) Wednesday b) Friday c) Thursday d) Sunday

**Answer : D**

**Explanation:**

**Wipro Previous Placement Questions solved – Calendars Model Question 5**

^{th}August of a year falls on Wednesday, then what day is the 2nd October in that year?

a) Wednesday b) Tuesday c) Monday d) Sunday

**Answer :B**

**Explanation:**

Number of days from 16th august and 2nd October is

^{nd}October = Wednesday + 6 = Tuesday

**Wipro Placement Papers solved – Model Question 6**

a) Monday b) Wednesday c) Thursday d) Sunday

**Answer : C**

**Explanation**: The number of days from January 1, 2008 to January 1

^{st}, 2009= 366 days ( Because 2008 is a leap year )

^{st},2009 is 2 days after Tuesday = Tuesday + 2 =Thursday

**Wipro Previous Placement Model Questions – Problems on Calendars 7**

a)Sunday b)Thursday c)Tuesday d) Friday

**Answer: D**

**Explanation:**The number of day from 8

^{th}December 2007 to 8

^{th}December 2006= 365 days = 52 weeks + 1 day.

**Wipro Placement Papers solved –Calendars Model Question 8**

a) Tuesday b) Monday c) Sunday d) Wednesday

**Answer : C**

Explanation:

Explanation:

^{th}February = Tuesday -2 = Sunday

**Wipro Placement Questions Solved –Model Question 9**

a) Monday b) Tuesday c) Wednesday d) Friday

**Answer : B**

Explanation

Explanation

**:**The number of days between 2 dates is = 365 days ( 2004 is a leap year , but while counting the number of days , February 29

^{th}is not taken )

^{th}March 2004 is 1 day behind the Wednesday = Wednesday -1 = Tuesday

**Wipro Placement Papers - Problems on Calendars Model Question 10**

a) Monday b) Wednesday c) Thursday d) Friday

**Answer :C**

**Explanation :**January 1

^{st}1 AD falls on Monday.

^{st}, 1 A.D to 26

^{th}January , 1950.

1950 January 26

^{th}can be written as = 1600 years + 300 years + 49 years + 26

Number of odd days till 1600 years = 0

1600 to 1900 = 300 years = 1 odd day.

49 years contains = 37 ordinary years + 12 leap years =37 + (12 × 2)

In January , 25 days = 25/7 =4 odd days

Total odd days =0 + 1 + 5 + 4 = 10/7 = 3 odd days

So 26th January,1950 is Monday + 3 = Thursday

**Wipro Placement Papers– Model Problems on Calendars 11**

a) Monday b) Wednesday c) Friday d) Sunday

**Answer : A**

Explanation :

Explanation :

January 1

^{st}1 AD falls on Monday.

^{st}, 1 A.D to 25

^{th}December , 1995.

1950 January 26

^{th}can be written as = 1600 years + 300 years + 94 years + and months up to November + 25 days in December

Number of odd days till 1600 years = 0

1600 to 1900 = 300 years = 1 odd day.

94 years contains = 71 ordinary years + 23 leap years

So 25th December 1995 falls on Monday+1 = Tuesday

**Wipro Latest Placement Questions – Model Question 12**

**Answer: c**

Explanation:

Explanation:

^{st}1 AD falls on Monday.

^{st}, 1 A.D to 16

^{th}July, 1776.

1950 January 26

^{th}can be written as = 1600 years + 100 years + 75 years + January to June months + July 16 days

Number of odd days till 1600 years = 0

1601 to 1700 = 100 years = 5 odd days

1701 to 1775 = 18 leap years + 57 ordinary years

Total odd days = 5 + 2 + 1 = 8 = 1 odd day.

Hence , 15

^{th}July 1776 falls on => Monday + 1 = Tuesday