**21.**A monkey could climb 3 meters of a round wet pole in the first minute but slipped down 1 meter in next minute .The climbing and slipped occurs every alternate minute. What time will the monkey take to reach the top of the pole which is 31 meters long?

a)25
minutes b)29 minutes c)30 minutes d)32 minutes

**Answer : B**

**Explanation :**

Every 2 minutes, the money climbs 3-1 = 2 meters.

In 28 minutes it will
climb 28 meters.

Remaining height to climb is = 31-28
= 3 meters

In 29

^{th}minute, the monkey will cover the last 3 minutes and reach the top of the pole .**22.**

**A man takes 8 hours in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. What time would he take to walk both ways?**

a)4
hours b)8 hours c)10 hours d)12 hours

**Answer : C**

**Explanation :**

Time taken in walking one way and riding back = 8 hours.

Time taken in riding both
ways = 2 hours less than W+R = 8-2 = 6 hours.

Time taken to
ride one way=

6
2

= 3 hours
Time taken in walking 1 way = (Walk
in 1 way + Ride in 1 way) – Ride in 1 way

= 8 -3 = 5 hours

Time taken in walking two days = 5+5
= 10 hours.

**23**. Two cars P and Q start from the same point and move in opposite direction at speeds of 35 kmph and 30 kmph. After how much time they will meet, if the distance between the P and Q is 357.5 kilometers?

a)4
hours b) 5 hours c)5 hours 30 minutes d)6 hours

**Answer:C**

**Explanation:**

Two cars are moving in opposite direction, their relative speed is the sum of their speeds.

Relative Speed = 35 kmph + 30 kmph = 65 kmph

Distance between P and Q =
357.5 kilometers

Time =

Distance
Speed

=
357.5
65

=
5.5 hours
They will meet after 5.5 hours

**24.**

**A and B are travelling in the same direction and A is 200 meters ahead of B.And speed of A is 12 m/s and speed of B is 8m/s.How much would be the distance between them after 15 more seconds?**

a)
160m b)140 m c)260m d)300m

**Answer :C**

**Explanation:**Initially the distance between A and B is 200 meters.

As A and B both
are moving in same direction, their relative speed is the difference of their
speeds.

Relative speed = 12-8= 4 m/s.

Means in every
second, A travels 4 meters more than B.

In 15 seconds, A will increase his lead by
15x4 = 60 meters.

Therefore, after
15 more seconds, the distance between A and B will be 200 meters + 60 meters
=260 meters

**25.**The distance between Bangalore and Kakinada is 1000 km. A car starts from Bangalore towards Kakinada at 6 a.m at an average speed of 60 km/h. Another car starts from Kakinada towards Bangalore at the same time at an average speed of 40 kmph. How far from Bangalore will the two cars meet?

a)
400 km b)600
km c)550 km d)450 km

**Answer:**

**Explanation:**The distance between two cities = 1000 km

Speed of the Car starts from Bangalore=
60 kmph

Speed of the car starts from Kakinada
= 40 kmph

Two are travelling in opposite direction,
relative speed = 60+40 = 100 kmph.

Time taken to meet each other =

Distance
Speed

=
1000
100

= 10 hours
Car
started from Bangalore travelled 10 hours.

Therefore, distance from Bangalore= Speed of
the car started from Bangalore x Time =
60 x 10 = 600 km

**26.**Two vehicles A and B are travelling towards each other from two different places 198 kms apart. The ratio of the speed of the vehicles A and B is 5:6 and the speed of the vehicle A is 60 kmph. After what time will the two vehicles meet each other?

a)
30 min b)
45 min c)1 hour d)1 hour 30 minutes

**Answer: D**

**Explanation :**Given that speed of the vehicle A= 80 kmph

The ratio of the speeds of A and B
= 5:6

Speed of vehicle A =
5x=60

Now speed of vehicle B = 6x= 72 kmph.

As both vehicles are travelling towards each
other, they are moving in opposite direction => Relative speed = 60+72= 132 kmph

Time taken to meet each other = Distance
between two places/Relative speed

=

198
132

=1.5 hours.
Therefore, two
vehicles meet other after 1 hour 30 minutes

**27.**A thief steals a motorbike at 8 a.m and rides the bike at an average speed of 40 kmph. The theft was discovered at 9.30 a.m and the policeman started chasing on another bike at a speed of 70kmph. When will he catch the thief ?

a)
10.30 a.m b)11.30
a.m c)12 noon d) He cannot catch him at all

**Answer: B**

**Explanation :**Thief stealth the car at 8 a.m and rides at a speed of 40 kmph

Theft was
discovered at 9.30 a.m

In
1 hour 30 minutes, thief travels = 40 x 1 hour 30 minutes = 60 km.

Therefore,
thief was 60 km ahead of policeman.

At
9.30 policeman started chasing at a speed of 70 kmph.

As
they both are moving in same direction, relative speed = 70-40 = 30 kmph

Time taken by policeman to cover 60 km
travelled by thief already =

Distance
Relative Speed

=

60
30

= 2 hours.
Starting
counting 2 hours from 9.30 a.m , thief will be caught at 11.30 am.

**28.**A businessman travels 600 km in 8 hours , partly by train and partly by his own car, If he had travelled all the way by his train, he would have saved

2
3

of
the time he travelled in his own car and would have reached 3 hour earlier.
What is the distance covered by car ?
a)
250 km b)220
km c)180 km d)100 km

**Answer:D**

**Explanation :**Difference in time of 1 ho9ur is due to saving in time resulting from that distance being covered by the train instead of car.

2
3

rd time in car = 3
hour
Total time in car= 3 x

3
2

= 4.5 hours
Time spend in train journey = 8-4.5= 3.5
hours.

If all the
distance were covered by train, the time taken is 8-3 = 5 hours.

In 5 hours, the distance covered by
train is 600 km.

In 3.5 hours , distance covered
by train =

600
5

x 3.5=420 km.
Therefore, the distance covered by car=
600- 420 = 180 km

**29.**A man wants to cover a distance of 45 km on his bicycle and his speed is 15 kmph. After 9 km, he takes rest for 15 min. How long will he take to cover the whole distance ?

a)
4 hours b)4
hours 15 minutes c)5 hours d)5 hours 15 minutes

**Answer:A**

**Explanation :**Speed of the cyclist = 15 kmph

Total distance to
be covered =45km

Therefore time taken by him to cover
45 km=

Distance
Speed

=
45
15

= 3 hours.
Cyclist has taken rest
after every 9 km, so in total he took
rest 4 times.

So, total time = 3 hours + 4 x 15 minutes = 4 hours

**30.**Vehicle A starts from P to Q and another vehicle B starts from Q to P. Both vehicles meet each other at midpoint of P and Q. After they meet each other, they complete their remaining journey in 3 hours and 2 hours respectively. What is the ratio of the time taken by both vehicles for whole journey ?

a)
2 :3 b)3:2 c)8:5 d)9:4

**Answer : B**

**Explanation :**Time taken by bus to cover half the distance = 3 hours

∴ Time taken by
vehicle A to cover complete distance= 2x3= 6 hours

Time taken by vehicle B to cover half the
distance = 2 hours

Time taken by Vehicle B to cover total
distance = 2 x 2 = 4 hours.

∴ The ratio of times taken
by vehicle A to vehicle B for whole journey
= 6 hours : 4 hours = 3:2

**31.**

**Two guns were fired from the same place at interval of 15 minutes. A person in car approaching the place hears the 2**

^{nd}13 minutes after the 1

^{st}. Find the speed of the car , if the sound travels at 80 m/s.

a)
15 m/s b)14
m/s c)12.3 m/s d)11.5 m/s

**Answer: C**

**Explanation:**If the car were not moving, the person would have heard the two sounds at an interval of 15 minutes.

The distance travelled by car in 13 minutes
is equal to the distance travelled by sound in 15-13 = 2 minutes.

Distance travelled by sound in 2
minutes = 80 x 120 sec =9600 meters

So the distance travelled by car in 13
minutes is 9600 meters.

∴ In 1 second , the car travels =

9600
13 x 60

=12.3 meters
Therefore , the speed of the car =
12.3 mps

**32.**Sudheer driving in the morning fog passes a pedestrian who was walking at the rate of 2 km/h in the same direction. The pedestrian can see the car for 6 minutes and upto distance of 0.8 km. Find the speed of the car ?

a)
8kmph b)10
kmph c)12 kmph d)12.5 kmph

**Answer : B**

**Explanation :**Time is 6 minutes =

6
60

hours =
1
10

hoursDistance covered by man in 6 minutes = 2 kmph x

6
60

=
0.2 kmDistance covered by car in 6 minutes = 0.2 km+ 0.8 km = 1 km

Speed of the car =

Distance
Time

=
1 km
6

=10 kmph**Alternate Method :**

Let the speed of the
car be x. and Speed of car= 2 kmph

Time is 6
minutes = 6/60 hours =1/10 hours

Sudheer and pedestrian are moving
in same direction=> Relative speed= x-2

Speed
= Distance by time

x-2 =

0.8
1/10

=> x= 10 kmph**33.**A car starts from A towards B and another starts from B towards A. The distance between A and B is 180 km. If the two cars travel in same direction ( from A towards B) they meet after 6 hours and if they travel in opposite direction, they will meet after 2 hours. What is the speed of the car starting from A?

a)
55 kmph b)58
kmph c)60 kmph d)72 kmph

**Answer :C**

**Explanation:**According to the question,

Let speed of the car starts from A is x
and speed of the car starts from B is y.

the distance between two places is 180 km

Time taken to cover 180 km distance when
they move in opposite direction = 2 hours

So their relative speed = x+y =

180
2

= 90 kmph
Time taken to
cover 180km distance when they move in same direction is 6 hours.

Then relative speed = x-y=

180
6

= 30 kmph
On solving x+y=90 and x-y= 30 , we get x=60 kmph.

**34**. Sharma started going walking for morning walk every day. The distance he walked on first day is 4 kms. Every day Sharma walks half of the distance he walked on the previous day. What can be the maximum total distance he walked in his life time?

a)
20 km b)12
km c)10 km d) 8 km

**Answer :**

**Explanation :**

The distance walked by Sharma on first day= 4 kms.

Every day he walks half the distance he
walking on the previous day.

Therefore, the distance walked =
4+2+

1
2

+
1
4

+ ….
The series is in GP . First term a=4 and common ratio=

1
2

.
Maximum total distance walked by Sharma in his
life time would be infinite. Hence, the series would be an infinite Geometric
series.

Sum of the terms of infinite
geometric series =

a
1-r

=
4
(1-1/2)

= 8 kms
35. Ravi starts
walks from A towards B , a distance of 67
km at the rate of 13 kmph. An hour later Ram starts his journey at B towards A
and walks at the rate of 5 kmph . Where
will Ravi meet Ram from B?

a)
12 km b)15
km c)18 km d)21 km

**Answer:B**

**Explanation:**

Ravi already gone 13 km in 1 hour when Ram starts.

Remaining distance = 67 km – 13 km= 54
km

Now speeds
of Ravi and Ram are 13 kmph and 5 kmph
and they travel in opposite direction

∴ They together cover
(13 +5) = 18 km in one hour.

Time taken to cover remaining 54 km =

Time taken to cover remaining 54 km =

Distance
Speed

=
54
18

= 3 hours.