Directions (15): Study the following table
carefully to answer the questions that follow:
Percentage of Marks Obtained by Six Students in Five Different
Subjects in A School Examination
Subject Student

English
(50)

Maths(100)

Science (150)

Hindi (50)

Social Studies (75)

P

66

89

80

78

84

Q

58

79

64

82

60

R

62

77

74

84

88

S

72

67

84

74

68

T

70

81

70

76

64

U

64

83

60

88

70

(United
Bank Of India PO Exam. 14.11.2010)
1. What is the approximate overall
percentage of marks obtained by U in all the subjects together?
a) 75% b) 71% c) 79% d) 82% e)
87%
Answer : B
Explanation :
Marks obtained by U:
English : 50 x $\frac{64}{100}$
= 32
Maths : 100 x$\frac{83}{100}$ =83
Science : 150 x $\frac{64}{100}$ = 90
Hindi : 50 x $\frac{88}{100}$ = 44
Social studies : 75 x $\frac{70}{100}$ =
52.5
Total marks obtained= 32 + 83 + 90
+ 44 + 52.5 = 301.5
Total maximum marks of all
subjects = 50+100+150+50+75 = 425
∴ Required percentage =$\frac{301.5}{425}$ x
100 =71%
2. In
order to pass the examination a minimum of 109.5 marks are requited in Science,
how many students pass in the examination?
a)Zero b)One c)Two d)Three e) Four
Answer : D
Explanation :
Minimum
marks to pass in Science = 109.5
So
percentage of pass marks = $\frac{109.5}{150}$ x 100% =73%
It is
obvious from the table that three
students P, R, and S got 73% of marks.
So three
students passed.
3. What
are the average marks obtained by all the students together in Hindi?
a) 36 1/6 b) 40 1/6 c) 41 1/3 d) 44 1/3 e)
None of these
Answer : B
Explanation: Average percentage of marks obtained by all
the students together in Hindi
= $\frac{(78+82+84+74+76+88)}{6}$ = $\frac{492}{6}$ = $\frac{241}{3}$
= $\frac{(78+82+84+74+76+88)}{6}$ = $\frac{492}{6}$ = $\frac{241}{3}$
Maximum marks in Hindi = 50
Average marks obtained by all the students together in Hindi = 50 x $\frac{241}{300}$ = 40 1/6
4. What is the average percentage of marks
obtained by all students together in English? (rounded to the nearest integer)
a) 62 b) 63 c) 70 d) 65 e) 56
Answer : D
Explanation :
Average percentage
of marks obtained by all students together in English
=$\frac{(66+ 58 +62+ 72+70+64)}{6}$ = $frac{392}{6}$ = 65.33%
=$\frac{(66+ 58 +62+ 72+70+64)}{6}$ = $frac{392}{6}$ = 65.33%
Rounded to the nearest integer, 65%
5. What
are the total marks obtained by S in all the subjects together?
a) 317 b) 309 c)
323 d)
348 e)
None of these
Answer: A
Explanation:
Marks obtained by S in each
subject :
English : 50 x $\frac{72}{100}$
= 36
Maths : 100 x $\frac{67}{100}$ = 67
Science : 150 x $\frac{84}{100}$ = 126
Hindi : 50 x $\frac{74}{100}$ = 37
Social Science : 68 x $\frac{75}{100}$ = 51
Total marks obtained by S in all
the subjects together = 36 + 67 + 126 + 37 +51 = 317
Directions (15): Study the following table
carefully to answer the questions given below it:
Number of candidates appearing for an interview for a post in
various Banks and percentage of candidates qualifying
Banks

Candidates Appearing

% of Candidates Qualifying

H

1500

14

I

2200

26

J

3000

17

K

980

20

L

1200

28

M

2500

21

(PNB
2010)
1. The number of candidates who did not qualify
in bank K was approximately what
percent of the candidates who did not qualify in bank I?
a) 48 b) 51 c) 42 d) 44 e)
53
Answer: A
Explanation :
Percentage
of nonqualified candidates = 100% 
Percentage of candidates qualifying
Number of nonqualified
candidates:
Bank K => 980 x $\frac{10020}{100}$
=> 980 x $\frac{80}{100}$ = 784
Bank I => 2200 x $\frac{10026}{100}$
=> 2200 x $\frac{74}{100}$ = 1628
Required percentage = $\frac{784}{1628}$ x
100% = 48.15% = 48% approximately
2. What was the respective ratio of the number of
candidates who qualified in bank H to the number of candidates who qualified in
bank L?
a)2 : 5 b) 5 : 6 c) 3 : 7 d) 5 : 8 e)
None of these
Answer : D
Explanation:
Number of candidates who qualified
in bank H = 1500 x $\frac{14}{100}$ = 210
Number of candidates who qualified
in bank L = 1200 x $\frac{28}{100}$ = 336
Required ratio = 210 : 336 = 5 : 8
3. What
was the average number of candidates who appeared for the interview in bank H,
J and L together?
a) 1800 b) 2000 c) 1500 d) 1700 e)
1800
Answer : E
Explanation:
Average
number of candidates who appeared for the interview in bank H, J and L together
=
$\frac{1500+3000+1200}{3}$ =$\frac{5700}{3}$ = 1900
$\frac{1500+3000+1200}{3}$ =$\frac{5700}{3}$ = 1900
4. What was the difference between the number of
candidates who qualified in banks I and J together and the number of candidates
who did not qualify in the same banks?
a) 3028 b) 3040 c) 3036 d) 3032 e)
None of these
Answer : C
Explanation:
Number of qualified candidates in
bank I = 2200 x $\frac{26}{100}$= 572
Number of nonqualified candidates
in bank I= 2200572 =1628
Number of qualified candidates in
bank J 3000 x $\frac{17}{100}$ = 510
Number of nonqualified candidates
in bank J= 3000 – 510 = 2490
∴ Required difference =( 1628 + 2490) –( 572 + 510) = 3036
5. What was the total number of candidates
qualifying in banks K, L, and M together?
a) 1042 b) 1057 c) 1050 d) 1045 e)
None of these
Answer : B
Solution: Number
of candidates who qualified in banks:
Bank K => 980 x $\frac{20}{100}$ = 126
Bank L => 1200 x $\frac{28}{100}$ = 336
Bank M => 2500 x $\frac{21}{100}$ =525
Total number of candidates
qualifying in banks K , L and M together