DATA INTERPRETATION  Tables
Directions (1 to 5): Study the
following table carefully to answer the questions that follow:
Percentage of Marks Obtained by
Six Students in Five Different Subjects in A School Examination
Subject
Student

Arithmetic (75)

Reasoning
(100)

English
(150)

GK
(50)

Computers
(75)

A

80

89

80

75

65

B

48

61

65

80

75

C

72

85

70

64

68

D

68

57

84

44

70

E

60

81

65

86

40

F

54

73

55

78

35

1. What is the approximate overall
percentage of marks obtained by F in all the subjects together?
a) 58% b) 72% c) 79% d)
82% e) 87%
Answer : (a)
Explanation: Total marks obtained by F
= 75 x $\frac{54}{100}$ + 100
x $\frac{73}{100}$ + 150 x $\frac{55}{100}$ + 50 x $\frac{78}{100}$ +
75 x $\frac{35}{100}$
= 40.5 +73+82.5+39+26.25
= 261.25
Total maximum marks in all the subjects = 75+100+150+50+75 =450
∴ Overall percentage of marks of F
in all the subjects = 261.25/450 x 100
=58%
2. The minimum marks to pass
Arithmetic subject is 52.5. Then how many students passed in the examination?
a) None b) Two c)
One d)
Three e) None of these
Answer : b
Solution: Pass marks in arithmetic is 52.5
Marks of each student in arithmetic
A= $\frac{80}{100}$ x 75 = 60 B= $\frac{73}{100}$ x75 =36
C= $\frac{73}{100}$ x 75 = 54 D=$\frac{73}{100}$ x 75 = 51
E=$\frac{60}{100}$ x 75 = 45 F=
$\frac{54}{100}$x 75=40.5
∴ Two Students A, C are passed.
3. What are the average marks
obtained by all the students together in Computers?
a) 36.66 b) 53 c) 42 d)
43.75 e) None of these
Answer :
Explanation:
Average percentage of all students in Computers = (65+75+68+70+40+35)/6 =58.83
Average percentage of all students in Computers = (65+75+68+70+40+35)/6 =58.83
Average marks of all students in the subject Computers = $\frac{58.83}{100}$
x 75 =43.75
4. What is the average percentage of marks
obtained by all students together in Reasoning? (rounded to the nearest
integer)
a) 46 b) 79 c) 65 d)
68 e) None of these
Answer: E
Explanation :
Average percentage of marks in Reasoning = (89+61+85+57+81+73)/6
= 74.33 = 74 ( Rounded off to
nearest integer)
5. What is the difference between
total marks obtained by A and D in all
the subjects together?
a) 57 b) 47 c) 323 d) 348 e) None of these
Answer. b
Explanation:
Total marks obtained by A = $\frac{80}{100}$ x 75 + $\frac{89}{100}$ x 100 + $\frac{80}{100}$x
150 + $\frac{75}{100}$ x 50 + $\frac{65}{100}$ x 75
= 60+89+120+37.5+48.75=355.25
= 60+89+120+37.5+48.75=355.25
Total marks obtained by D = $\frac{68}{100}$ x 75 + $\frac{57}{100}$ x 100 + $\frac{84}{100}$ x
150 + $\frac{44}{100}$ x 50 + $\frac{70}{100}$ x 75
= 51+57+126+22+52.5=308.25
= 51+57+126+22+52.5=308.25
Therefore, required difference =355.25 – 308.25 =47
Directions (1 to 5): Study the following table
carefully to answer the questions given below it:
Population of 5 villages and
percentage of graduates in each village
Village

Population

% of Graduates

P

2500

16

Q

3200

30

R

4000

18

S

1980

20

T

2200

25

U

1500

27

1. The number of people who are not graduates in
village Q was approximately what
percent of the people who did not complete their graduation in village U?
a) 205 % b) 125% c) 49% d) 44 e)
None of these
Answer : C
Explanation: Number
of people who didn’t complete their graduation:
Village Q Ãž 3200 x $\frac{73}{100}$ = 2240
Village U Ãž= 1500 x $\frac{73}{100}$ =1095
Required percentage = 2240/1095 x
100% =205%
2. What was the respective ratio of number of
graduates in village S to number of graduates in village R ?
a)2 : 5 b) 11 : 20 c) 13 :17 d)
15 : 8 e) None of these
Answer : B
Explanation: Number of
graduates in village S = 1980 X $\frac{20}{100}$ = 396
Number of graduates in village R = 4000 X $\frac{18}{100}$ = 720
Therefore, required ratio = 396 : 720= 11: 20
3. What was the average population of three villages
Q, T and U ?
a) 1800 b) 2400 c) 1800 d) 2300 e)
None of these
Answer :D
Explanation: Required
average = 3200 + 2200 +1500 /3=6900/3 =2300
4. What was the difference between the number of graduates
in villages P and R together and the number of non graduates in the same
villages together?
a) 5380 b)3280 c) 4260 d) 4062 e)
None of these
Answer : C
Explanation: Number
of graduates in village P = 2500 x $\frac{16}{100}$ = 400
Number of non graduates in village
P = 2500 400 =2100
Number of graduates in village R =
4000 x $\frac{18}{100}$ = 720
Number of non graduates in village
R = 4000 720 =3280
∴ Required difference
= (3280+2100) – (400+720) = 4260
5. What was the average number of graduates in villages
all six villages together?
a) 400 b) 460.5 c) 472 d) 560.5 e) None of these
Answer : b
Number of graduates in village P = 2500 x $\frac{16}{100}$ =400
Number of graduates in village Q = 3200 x $\frac{16}{100}$ =512
Number of graduates in village R = 4000 x $\frac{18}{100}$ =720
Number of graduates in village S = 1980 x $\frac{20}{100}$ =396
Number of graduates in village T = 2200 x $\frac{15}{100}$ =330
Number of graduates in village U = 1500 x $\frac{27}{100}$ =405
Required
average = (400 +512 +720+396+330+405)/6 = 2763/6= 460.5